seven

Hi, I searched the tech forum could not find the answer I was looking for ,pretty sure the procedure I found is correct but this is my question .. I picked up a 2001 cherokee with the infamous 0331 crack head. I purchased the new heavy duty head from our local machine shop Colvin in Long Island who said they are selling quite a few of these paid 465. with new valves installed anyway that is on and torqued down.. I am doing the rocker arms and pushrods ,the only procedure I can find is that they tell you to inspect pushrods install them back in original position if good , put #1 piston at top dead center and torqe each rocker to 19 lbs?? but leave the #1 piston at tdc?? Is this correct or as you move down do you bring the piston you are working on up to tdc?? On gm cars that is how you would do it if I remember right but not sure on the I6 ?? Any help or advice is greatly appreciated Thanks and have a good one Bill or seven maybe 8 lol

CCKen

Bring each cylinder you are working with to TDC compression.

Firing order is 153624, so the next cylinder you will be installing the rockers on is #5, etc. If you remove the distributor cap and with #1 at TDC compression, the rotor will be just past the #1 cap terminal. Rotating the crankshaft with a 3/4" socket clockwise 120 degrees will bring the rotor to just past the #5 cap terminal, and so forth for each cylinder in firing order.

Edit: Oops, the 2001 doesn't have a distributor. LOL

Rotating the crank 120 degrees will bring you to TDC compression on #5, but you'll need to feel for air pushing out #5 spark plug hole to comfirm you are on compression.

I think the rocker cap screws are torqued to 21 ft./lbs. if I'm not mistaken.

freegdr

Did you remove dist.If not just throw rockers on and tighten them down.