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wheels and mpg's

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Old Apr 6, 2011 | 11:47 AM
  #16  
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Originally Posted by N20jeep
I don't agree with this

So you're saying unsprung weight has no effect on mpg's or performance?

Weight is weight, whether its sprung or not your motor still has to carry that load. It doesn't just go away if its unsprung
Force=mass*acceleration

if there is no acceleration mass will not come into play
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Old Apr 6, 2011 | 11:55 AM
  #17  
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Originally Posted by 96_xj
I can write you the entire equation if you want. I did a whole semester on rotational mass as one of my mechanical engineering projects to prep for my internship at Boeing.
you are confusing yourself here by throwing inertia into the equation. inertia will never helping a vehicle do anything except cruise farther with foot off the pedal.

also, I would like to know who on this website spends more time going a constant speed than accelerating? Remember that when youre on the freeway, how often are you ACTUALLY staying the same speed? I know I pretty much never do.

http://www.northamericanmotoring.com...s-mileage.html

to be honest, you are arguing against personal experience, so youre obviously not correct. on top of my experience, I have a friend who changed from 50 lb combo to a 35 lb combo, same wheel diameter, same tires, and picked up 4 mpg. Thats an average over his other tanks and he is weird and actually keeps track of each tank. you cant argue with that...
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Old Apr 6, 2011 | 11:55 AM
  #18  
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Originally Posted by captainofiron

Force=mass*acceleration

if there is no acceleration mass will not come into play
So you don't hit the gas peddle while driving?

Sure at idle, mpgs won't change.

But in the real world, where people actually drive it will
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Old Apr 6, 2011 | 11:55 AM
  #19  
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Btw here is the equation that I used to formulate the differences in dead weight vs sprung weight (again this is related to a bike which in theory/actuality is the same as a vehicle). This is directly quoted from my project
Attached Thumbnails wheels and mpg's-screen-shot-2011-04-06-10.56.07-am.jpg  
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Old Apr 6, 2011 | 11:57 AM
  #20  
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Originally Posted by captainofiron
a wheel doesnt have friction acting upon it unless its sliding or accelerating

seriously man you are really starting to show your ignorance

the reason you have to keep adding energy is to counteract the forces of drag on the cars body as well as the rolling resistance of the tire
the wheel itself doesnt have much friction and the difference between aluminum and steel probably doesnt exist (air hits the wheel and causes friction...negligible). but the wheel is attached to the tire, which you admit encounters rolling resistance. you cant accelerate the tire to overcome this without accelerating the wheel
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Old Apr 6, 2011 | 11:57 AM
  #21  
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Originally Posted by N20jeep
So you don't hit the gas peddle while driving?

Sure at idle, mpgs won't change.

But in the real world, where people actually drive it will
yes, but you hold the gas peddle steady true?

if what you are saying was correct then you would have to gradually apply more and more pressure to the pedal
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Old Apr 6, 2011 | 11:58 AM
  #22  
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Originally Posted by Hoooper
the wheel itself doesnt have much friction and the difference between aluminum and steel probably doesnt exist (air hits the wheel and causes friction...negligible). but the wheel is attached to the tire, which you admit encounters rolling resistance. you cant accelerate the tire to overcome this without accelerating the wheel
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Old Apr 6, 2011 | 12:00 PM
  #23  
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Originally Posted by captainofiron
Force=mass*acceleration

if there is no acceleration mass will not come into play
Coulomb friction, named after Charles-Augustin de Coulomb, is an approximate model used to calculate the force of dry friction. It is governed by the equation:
where
  • is the force exerted by friction by each surface on the other. It is parallel to the surface, in a direction opposite to the net applied force.
  • is the coefficient of friction, which is an empirical property of the contacting materials,
  • is the normal force exerted by each surface on the other, directed perpendicular (normal) to the surface.
how do you overcome the force of friction to maintain a constant speed without providing force through the wheel
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Old Apr 6, 2011 | 12:01 PM
  #24  
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Originally Posted by Hoooper
you are confusing yourself here by throwing inertia into the equation. inertia will never helping a vehicle do anything except cruise farther with foot off the pedal.

Inertia is a VERY important part of the equation tho. it is in every day-to-day driving scenario.

when cruising at speed. (which I make 300+ mile trips often) that rotation mass working for you keep you at speed will help drop the RPM's maybe only 10rpms, but that 10 rpms over 300 miles at a consistent 75 mph which is about 4 hours or 240 minutes is 2400 revolutions your engine does not have to turn.

granted the world is not perfect, but inertia is a VERY important part
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Old Apr 6, 2011 | 12:02 PM
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Originally Posted by captainofiron

yes, but you hold the gas peddle steady true?

if what you are saying was correct then you would have to gradually apply more and more pressure to the pedal
No, that's not what I'm saying.


Stop and go traffic, getting up to speed, passing, driving up hill all require acceleration. Most driving isn't just sitting at one single speed. It's constantly changing during daily driving.
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Old Apr 6, 2011 | 12:05 PM
  #26  
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Originally Posted by N20jeep
No, that's not what I'm saying.


Stop and go traffic, getting up to speed, passing, driving up hill all require acceleration. Most driving isn't just sitting at one single speed. It's constantly changing during daily driving.


and for ever action there is an equal or opposite reaction.

meaning that for every uphill you have to go down hill, for every acceleration off the green stop light you have to decelerate at every red light.

it comes out NEARLY equal and consistent in the end over a large data sample
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Old Apr 6, 2011 | 12:06 PM
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Originally Posted by captainofiron
yes, but you hold the gas peddle steady true?

if what you are saying was correct then you would have to gradually apply more and more pressure to the pedal
I dont think you understand angular acceleration. answer these questions

If you let off the gas, does your vehicle continue at a constant speed?

When you apply the gas, does the engine provide power to the wheels?

When your engine applies power to the wheels, is this a force?

Is force = mass * acceleration?
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Old Apr 6, 2011 | 12:09 PM
  #28  
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Originally Posted by 96_xj

and for ever action there is an equal or opposite reaction.

meaning that for every uphill you have to go down hill, for every acceleration off the green stop light you have to decelerate at every red light.

it comes out NEARLY equal and consistent in the end over a large data sample
It doesn't come out equal. You still have to slow that extra weight down. Which means higher braking force or longer stopping distance.

Getting that weight up to speed and back down Will require extra energy
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Old Apr 6, 2011 | 12:10 PM
  #29  
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Originally Posted by 96_xj
Inertia is a VERY important part of the equation tho. it is in every day-to-day driving scenario.

when cruising at speed. (which I make 300+ mile trips often) that rotation mass working for you keep you at speed will help drop the RPM's maybe only 10rpms, but that 10 rpms over 300 miles at a consistent 75 mph which is about 4 hours or 240 minutes is 2400 revolutions your engine does not have to turn.

granted the world is not perfect, but inertia is a VERY important part
unless youre cruising the freeway with an unlocked tq converter the RPM will be the same no matter what is on the end of the axle, the difference is the amount of power it takes to maintain speed. on the freeway, the difference is not as large as in town, but heavy wheels, once at speed, will continue to suck up power as they are forced to rotate, making them less efficient than lighter wheels. like I said, on the freeway its not as large of a difference but it is definitely still there and if the weight difference on the wheels is enough (10 lbs/wheel is definitely plenty) you will notice it in MPG
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Old Apr 6, 2011 | 12:11 PM
  #30  
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Originally Posted by 96_xj
and for ever action there is an equal or opposite reaction.

meaning that for every uphill you have to go down hill, for every acceleration off the green stop light you have to decelerate at every red light.

it comes out NEARLY equal and consistent in the end over a large data sample
what are you talking about? the rotational mass would help you if you needed to coast through red lights, not stop. the extra mass rotating doesnt help you use less gas while stopping for a red light...
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