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Poor mans locker, using the break.

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Old Mar 15, 2013 | 02:44 PM
  #91  
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Its awful funny tho....

This brake theory may work if you can apply the brake to only the spinning tire, creating more resistance to that wheel. Otherwise your adding resistance to both tires, and one side will still have more resistance than the other.

What this has to do with front axle torque vs rear axle torque boggles my mind...
Old Mar 15, 2013 | 02:54 PM
  #92  
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Originally Posted by Gee oh Dee

This brake theory may work if you can apply the brake to only the spinning tire, creating more resistance to that wheel. Otherwise your adding resistance to both tires, and one side will still have more resistance than the other.
Its Settled
Old Mar 15, 2013 | 02:55 PM
  #93  
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Originally Posted by JerrytheJeep
How bout a vertical mill or a lathe? The thing I cant understand is this whole idea of demand that you have, I can understand an engine or motor under load. but like with the mower, torque isn't instantaneously created the moment the blade hits the rock, it's always there. I already answered your question, anything beyond is just a pointless argument. If it is rotating, then there is torque. not just enough to overcome the weight of the pieces involved, but more than that. some greater unspecified amount. if you were to suddenly apply friction, with your brakes your hand or little bunny foo foo you will observe that amount. It's this sudden shock that causes the damage not the sudden appearance of torque, the sudden appearance of load that was not there before. Its like gravity, it isn't the fall that kills you, its the sudden stop.
Your wrong though and I proved your answer wrong. How can MAX mean the same as limit when max decribes the kind of limit, Max limit. By your logic min limit means minimum max? I dont think so.



Originally Posted by Rock Toy
I can not believe that this thread has gone for 6 pages.
Everyone wants to say Im wrong but no one til Jerry here has tried to say why. Fortunately for me Jerry isnt correct.

I get a kick out of everyone saying im wrong and having nothing to back it up. The "Seasoned" off roaders trying to tell me I dont know anything and that physics mean nothing when Im Quoting Differential manufactures supporting my claim is funny.
Old Mar 15, 2013 | 02:57 PM
  #94  
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Unless the OP can prove beyone any doubt that he got unstuck ONLY because he applied the brakes.

But there are way too many other factors. So many things could have happened as well.

Packed snow moved. Packed tires cleared and got more bite. Tires were spinning slower and got better grip. Etc.
Old Mar 15, 2013 | 03:04 PM
  #95  
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Originally Posted by Gee oh Dee
Unless the OP can prove beyone any doubt that he got unstuck ONLY because he applied the brakes.

But there are way too many other factors. So many things could have happened as well.

Packed snow moved. Packed tires cleared and got more bite. Tires were spinning slower and got better grip. Etc.

If we get some snow and ice tonight I play on getting a video dunno if itll be enough though.
Old Mar 15, 2013 | 03:09 PM
  #96  
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I'd still like to hear your explanation of our brake system.

Brakes are applied equally to the driver and passenger side tires. If one has no traction, you suggest applying the brakes to give resistance to the spinning tire.

However your applying equal brake pressure to those tires.

The resistance, although more overall, will still be different causing one to have more traction/resistance than the other...?
Old Mar 15, 2013 | 03:12 PM
  #97  
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And you'll still have to show that only applying the brakes is what got you "unstuck".

Simply stopping and allowing the tires to grab something may have been enough.

Thats gonna be hard to prove.
Old Mar 15, 2013 | 03:26 PM
  #98  
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Well jeeze...did I kill the buzz?

Old Mar 15, 2013 | 03:49 PM
  #99  
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Originally Posted by Gee oh Dee
I'd still like to hear your explanation of our brake system.

Brakes are applied equally to the driver and passenger side tires. If one has no traction, you suggest applying the brakes to give resistance to the spinning tire.

However your applying equal brake pressure to those tires.

The resistance, although more overall, will still be different causing one to have more traction/resistance than the other...?
Like I said earlier I wouldnt try this on rock when the wheels were really stuck, but if your stuck on ice or snow and need just a lil extra. Spinning the wheels faster will add some torque but with no load it will be low. Between using the brake for some resistance and gas to get over the braking friction and traction it can work.
Old Mar 15, 2013 | 03:50 PM
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Originally Posted by Gee oh Dee
And you'll still have to show that only applying the brakes is what got you "unstuck".

Simply stopping and allowing the tires to grab something may have been enough.

Thats gonna be hard to prove.

I figure find some ice and get one wheel on it. it should spin at idle and you wont move. Give some gas and break and be on your way.
Old Mar 15, 2013 | 03:53 PM
  #101  
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Originally Posted by Gee oh Dee
I'd still like to hear your explanation of our brake system.

Brakes are applied equally to the driver and passenger side tires. If one has no traction, you suggest applying the brakes to give resistance to the spinning tire.

However your applying equal brake pressure to those tires.

The resistance, although more overall, will still be different causing one to have more traction/resistance than the other...?
The thing is, the tire that isn't moving in this situation isn't "stuck". It doesn't require any extra power to get rolling. It just isn't getting any power at all because it's all going to the tire that is spinning.

Now apply some resistance to both tires via the brakes. The differential adjusts and begins sending some torque to both axles (I'm talking axle shafts, not the front/back axle tangent this thread went off on). If the torque to the tire that has traction is greater than the force on the brakes, then it should start to roll, right?

That's what makes the brakes work like a locker. The brake force is equal on both axles, so the open differential goes from sending all force to the tire that slips to sending the same force to both of them. Now the tire on the ice will slow down and the one that has traction will start turning.

Now if one tire is actually "stuck" in mud or something, then it's a different situation. But if one tire has good traction and the other is on ice or up in the air and has zero traction, then it seems like the brake trick should help, even though it is braking all wheels.

The problem is that the engine is trying to turn the axles and the brakes are trying to stop them. Those conflicting forces are going to find the weakest part in the drivetrain and try to break it, so I wouldn't overdo it.
Old Mar 15, 2013 | 04:01 PM
  #102  
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The overall resistance will still be uneven.

One tire will still have less resistance than the other...
Old Mar 15, 2013 | 04:03 PM
  #103  
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Hey guys. How does low speed traction control work? By applying the brake to the spinning wheel............................
Old Mar 15, 2013 | 04:07 PM
  #104  
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Originally Posted by Gee oh Dee
The overall resistance will still be uneven.

One tire will still have less resistance than the other...
So what? The tire that slips will spin a little faster than the one that grips then. The open differential isn't all or nothing. If you apply the brakes and get a 60/40 split of power, and that 40% is enough to overcome the brakes and get the tire rolling, then you're moving again. And if you hit the brakes and gas too hard and grenade the spiders, then you're f'ed.
Old Mar 15, 2013 | 04:07 PM
  #105  
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Originally Posted by cruiser54
Hey guys. How does low speed traction control work? By applying the brake to the spinning wheel............................


Just the spinning wheel or to both wheels on that axle?



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