cruiser54

First off, the correct spellin is BRAKE.

Secondly, a spinning wheel can be "braked" causing the power to shift to the non-spinning wheel.

arorton

Same can be stated about the OP... lol

Aaron N.S.

at the expense of your brake pads and drums/rotors, and your clutch/s

mr white

And possibly spiders.

CalstateXJ

Sorry!!! Was thinking about my thoughts. I'll watch myself next time.!!!! So with that said. Any side effects damage wise by doing this??

mr white

Yes. As mentioned previously.

No4x4Yet

only the amount of torque require to spin the tires. If this is on ice that almost zero.

your missing it. Applying thr]e brake require more power from the engine to spin the spin wheel. when the brake force equals the force of the tire with traction you move.

yes but with out traction the motor doesnt produce any torque.

might wanna read up on newtons laws as arorton pointed out.

This is wrong, ever have a car on a dyno? They load the dyno to read the pwoer. As arorton said torque in equals torque out. If there is no torque out there is not torque in.

Here we go so now we can make sense of things, Left tire is on ice, right on rocks. Left tire spins cuz it takes very little force (TORQUE) to slid on ice. Power in equals power out, there for a lil power out, slipping on ice equals a lil power in. so there isnt enough power to move the wheel with traction on the rocks.

no shift but demand more power from the engine giving the wheel that has TRACTION enough power to over come it and move you forwards.

Sorry its a lil mixed up but your guys were fast.

Lil reading for you guys. They say the same thing as me.

http://www.jeepforum.com/forum/f19/u...ction-1308169/

http://www.wranglerforum.com/f5/park...on-196737.html

Aaron N.S.

it stresses everything in your drive train, more so then having a locker would. think that having a locked axle, your traction tire is only applying as much resistance to the system as it would if both tires had traction, more or less. Now by applying the brakes your increasing the power needed to get the wheels moving by a factor of 4, since the truck has to spin all 4 tires while under braking. its very hard on everything, engine, trans t-case, shafts, diff's axle shafts, brake pads, rotor/drums. all the way around.


IT's one of those thing you do in an emergency, not as a common practice to replace a $2-300 locker

Aaron N.S.

It's not that the engine isn't producing enough power, it could make infinite power and you still wouldn't move the tire on the rock, it's a matter of resistance, the brake equals the resistance therefore preventing the wayward spin.

CalstateXJ

Got it. Thanks. I guess i should read first.

No4x4Yet

Im not sayin a every day thing at all but in a pinch it can help.

Now since applying the brake gets more torque to spin the stuck wheel equal torque would be applied to the front wheels correct?

Im not making this no torque this up its been discussed. The links I posted describe it a lil more clearly then I did.

wpwarren

In one of those threads they are talking about diffs with limited slips or true tracs. Using the brakes absolutely helps in that case. You are mistaken in the power in power out thing. That only works in static type situations. If the engine provides more torque to a tire than that tire can transmit to the ground, the engine does not cease to produce torque to that wheel. The wheel accelerates (spins). An engine provides torque to the wheels whether they are in the air or not. A dyno is loaded to measure horsepower primarily. Power equals force times velocity.

CalstateXJ

Thanks. Great information.

No4x4Yet

Post 6 and 31 on the Wrangler forum both say the same thing as me and post 31 specifically says open differentials. I personally tried this in the last snow storm we had when I got stuck Wheels were spinning I applied the brakes til they stopped and increased the gas and got the other wheels to move. Your logic doesnt explain how that is possible.

Also post 31 was be a vendor from a brake company. I would think that he would know a thing or two about the issue.

wpwarren

Post six violates the laws of physics, if that were true and you were to push on the gas more, the spinning tire could not spin any faster. However, because when you push on the gas the spinning wheel spins faster there must be a torque applied to it. You cannot have angular acceleration (tire spin) without torque. Anyone who has ever been stuck knows that if you push on the gas harder, the tire spins faster. Post 31 is straight up wrong. An open diff does not always split torque 50/50. A spool is the only way to always split torque 50/50 to each wheel. A performance differential maker I will trust on the subject, a brake manufacturer I will not. You were able to get unstuck because you applied less torque to the spinning wheel, not more. Static friction (what happens when a tire is rolling not spinning) is always greater than kinetic friction (what happens when a tire spins). By applying the brakes you use the friction force of the brakes to counteract some of the torque from the engine. This allows the tire to use the higher static frictional force to propel the vehicle forward.