Spring rate calculations?
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Originally Posted by No4x4Yet
Since the formula has apparently changed since I learned it. we need to discuss this?
A coil springs spring rate is determined by the overall movement of all the coils combined.
Example, lets say you have a coil spring with a spring rate of 100lbs per inch. And it has 10 coils, this means each of those coils will only need to move. 1/10" to equal the one inch drop, meaning it would take 10lbs per coil to equal that inch.
Now you take away one of the coils like you would by cutting a spring. Now you only have 9 coils. So instead of them only needing to move 1/10" each, they will now need to move 1/9"( which is more) to equal that same full inch of compression in the spring. Which means more pressure will need to be applied, since you now hace less coils to go the same distance. resulting in more OVERALL spring rate
#3
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Year: 2000
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Its not the formula you're getting wrong. Its the application. When dealing with multiple coils like on a vehicle spring, the way you determine it changes.
A coil springs spring rate is determined by the overall movement of all the coils combined.
Example, lets say you have a coil spring with a spring rate of 100lbs per inch. And it has 10 coils, this means each of those coils will only need to move. 1/10" to equal the one inch drop, meaning it would take 10lbs per coil to equal that inch.
Now you take away one of the coils like you would by cutting a spring. Now you only have 9 coils. So instead of them only needing to move 1/10" each, they will now need to move 1/9"( which is more) to equal that same full inch of compression in the spring. Which means more pressure will need to be applied, since you now hace less coils to go the same distance. resulting in more OVERALL spring rate
A coil springs spring rate is determined by the overall movement of all the coils combined.
Example, lets say you have a coil spring with a spring rate of 100lbs per inch. And it has 10 coils, this means each of those coils will only need to move. 1/10" to equal the one inch drop, meaning it would take 10lbs per coil to equal that inch.
Now you take away one of the coils like you would by cutting a spring. Now you only have 9 coils. So instead of them only needing to move 1/10" each, they will now need to move 1/9"( which is more) to equal that same full inch of compression in the spring. Which means more pressure will need to be applied, since you now hace less coils to go the same distance. resulting in more OVERALL spring rate
The coils at the top are stacked on top of each other. They arent gonna all umcompress while driving. You could remove 1-2 coils depending on the spring rate and suspension travel with now ill affects.
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That is a progressive rate coil, Which you only referenced once. And I don't know why that was even brought into the debate. Most of that conversation that I read was about cutting standard single rate coils... like our factory coils and most aftermarket coils.
And cutting those will change overall spring rate
And cutting those will change overall spring rate
Last edited by N20jeep; 05-30-2012 at 02:49 PM.
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That is a progressive rate coil, Which you only referenced once. And I don't know why that was even brought into the debate. Most of that conversation that I read was about cutting standard single rate coils... like our factory coils and most aftermarket coils.
And cutting those will change overall spring rate
And cutting those will change overall spring rate
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Year: 92
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Originally Posted by No4x4Yet
I could have sworn I had single rate springs on my mustang that bunch up at the bottom, but maybe Im wrong? Ill have to look into that.
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Originally Posted by N20jeep
It would have been progressive that does that. Single rate springs collapse equally throughout the coils
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Originally Posted by 93XJLI
im still confused
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As for the original topic of the discussion the F-150 springs, arent those overly stiff to begin with? So cutting a coil or two to get the desired height and a lower, more reasonable spring rate would actually be beneficial, no?